Optimal. Leaf size=76 \[ -\frac {1}{6} \tanh ^{-1}\left (\frac {x}{2}\right ) (d+4 f+16 h)+\frac {1}{3} \tanh ^{-1}(x) (d+f+h)-\frac {1}{6} \log \left (1-x^2\right ) (e+g+i)+\frac {1}{6} \log \left (4-x^2\right ) (e+4 g+16 i)+h x+\frac {i x^2}{2} \]
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Rubi [A] time = 0.19, antiderivative size = 76, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 8, integrand size = 38, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.210, Rules used = {1673, 1676, 1166, 207, 1663, 1657, 632, 31} \[ -\frac {1}{6} \tanh ^{-1}\left (\frac {x}{2}\right ) (d+4 f+16 h)+\frac {1}{3} \tanh ^{-1}(x) (d+f+h)-\frac {1}{6} \log \left (1-x^2\right ) (e+g+i)+\frac {1}{6} \log \left (4-x^2\right ) (e+4 g+16 i)+h x+\frac {i x^2}{2} \]
Antiderivative was successfully verified.
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Rule 31
Rule 207
Rule 632
Rule 1166
Rule 1657
Rule 1663
Rule 1673
Rule 1676
Rubi steps
\begin {align*} \int \frac {d+e x+f x^2+g x^3+h x^4+14 x^5}{4-5 x^2+x^4} \, dx &=\int \frac {x \left (e+g x^2+14 x^4\right )}{4-5 x^2+x^4} \, dx+\int \frac {d+f x^2+h x^4}{4-5 x^2+x^4} \, dx\\ &=\frac {1}{2} \operatorname {Subst}\left (\int \frac {e+g x+14 x^2}{4-5 x+x^2} \, dx,x,x^2\right )+\int \left (h+\frac {d-4 h+(f+5 h) x^2}{4-5 x^2+x^4}\right ) \, dx\\ &=h x+\frac {1}{2} \operatorname {Subst}\left (\int \left (14-\frac {56-e-(70+g) x}{4-5 x+x^2}\right ) \, dx,x,x^2\right )+\int \frac {d-4 h+(f+5 h) x^2}{4-5 x^2+x^4} \, dx\\ &=h x+7 x^2-\frac {1}{2} \operatorname {Subst}\left (\int \frac {56-e-(70+g) x}{4-5 x+x^2} \, dx,x,x^2\right )-\frac {1}{3} (d+f+h) \int \frac {1}{-1+x^2} \, dx+\frac {1}{3} (d+4 f+16 h) \int \frac {1}{-4+x^2} \, dx\\ &=h x+7 x^2-\frac {1}{6} (d+4 f+16 h) \tanh ^{-1}\left (\frac {x}{2}\right )+\frac {1}{3} (d+f+h) \tanh ^{-1}(x)-\frac {1}{6} (-224-e-4 g) \operatorname {Subst}\left (\int \frac {1}{-4+x} \, dx,x,x^2\right )-\frac {1}{6} (14+e+g) \operatorname {Subst}\left (\int \frac {1}{-1+x} \, dx,x,x^2\right )\\ &=h x+7 x^2-\frac {1}{6} (d+4 f+16 h) \tanh ^{-1}\left (\frac {x}{2}\right )+\frac {1}{3} (d+f+h) \tanh ^{-1}(x)-\frac {1}{6} (14+e+g) \log \left (1-x^2\right )+\frac {1}{6} (224+e+4 g) \log \left (4-x^2\right )\\ \end {align*}
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Mathematica [A] time = 0.06, size = 98, normalized size = 1.29 \[ \frac {1}{12} \left (-2 \log (1-x) (d+e+f+g+h+i)+\log (2-x) (d+2 e+4 (f+2 g+4 h+8 i))+2 \log (x+1) (d-e+f-g+h-i)-\log (x+2) (d-2 (e-2 f+4 g-8 h+16 i))+12 h x+6 i x^2\right ) \]
Antiderivative was successfully verified.
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fricas [A] time = 18.71, size = 88, normalized size = 1.16 \[ \frac {1}{2} \, i x^{2} + h x - \frac {1}{12} \, {\left (d - 2 \, e + 4 \, f - 8 \, g + 16 \, h - 32 \, i\right )} \log \left (x + 2\right ) + \frac {1}{6} \, {\left (d - e + f - g + h - i\right )} \log \left (x + 1\right ) - \frac {1}{6} \, {\left (d + e + f + g + h + i\right )} \log \left (x - 1\right ) + \frac {1}{12} \, {\left (d + 2 \, e + 4 \, f + 8 \, g + 16 \, h + 32 \, i\right )} \log \left (x - 2\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.26, size = 96, normalized size = 1.26 \[ \frac {1}{2} \, i x^{2} + h x - \frac {1}{12} \, {\left (d + 4 \, f - 8 \, g + 16 \, h - 32 \, i - 2 \, e\right )} \log \left ({\left | x + 2 \right |}\right ) + \frac {1}{6} \, {\left (d + f - g + h - i - e\right )} \log \left ({\left | x + 1 \right |}\right ) - \frac {1}{6} \, {\left (d + f + g + h + i + e\right )} \log \left ({\left | x - 1 \right |}\right ) + \frac {1}{12} \, {\left (d + 4 \, f + 8 \, g + 16 \, h + 32 \, i + 2 \, e\right )} \log \left ({\left | x - 2 \right |}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.01, size = 179, normalized size = 2.36 \[ \frac {i \,x^{2}}{2}-\frac {d \ln \left (x +2\right )}{12}+\frac {d \ln \left (x -2\right )}{12}-\frac {d \ln \left (x -1\right )}{6}+\frac {d \ln \left (x +1\right )}{6}+\frac {e \ln \left (x +2\right )}{6}+\frac {e \ln \left (x -2\right )}{6}-\frac {e \ln \left (x -1\right )}{6}-\frac {e \ln \left (x +1\right )}{6}-\frac {f \ln \left (x +2\right )}{3}+\frac {f \ln \left (x -2\right )}{3}-\frac {f \ln \left (x -1\right )}{6}+\frac {f \ln \left (x +1\right )}{6}+\frac {2 g \ln \left (x +2\right )}{3}+\frac {2 g \ln \left (x -2\right )}{3}-\frac {g \ln \left (x -1\right )}{6}-\frac {g \ln \left (x +1\right )}{6}+h x -\frac {4 h \ln \left (x +2\right )}{3}+\frac {4 h \ln \left (x -2\right )}{3}-\frac {h \ln \left (x -1\right )}{6}+\frac {h \ln \left (x +1\right )}{6}+\frac {8 i \ln \left (x +2\right )}{3}+\frac {8 i \ln \left (x -2\right )}{3}-\frac {i \ln \left (x -1\right )}{6}-\frac {i \ln \left (x +1\right )}{6} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 1.25, size = 88, normalized size = 1.16 \[ \frac {1}{2} \, i x^{2} + h x - \frac {1}{12} \, {\left (d - 2 \, e + 4 \, f - 8 \, g + 16 \, h - 32 \, i\right )} \log \left (x + 2\right ) + \frac {1}{6} \, {\left (d - e + f - g + h - i\right )} \log \left (x + 1\right ) - \frac {1}{6} \, {\left (d + e + f + g + h + i\right )} \log \left (x - 1\right ) + \frac {1}{12} \, {\left (d + 2 \, e + 4 \, f + 8 \, g + 16 \, h + 32 \, i\right )} \log \left (x - 2\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.19, size = 108, normalized size = 1.42 \[ h\,x+\frac {i\,x^2}{2}-\ln \left (x-1\right )\,\left (\frac {d}{6}+\frac {e}{6}+\frac {f}{6}+\frac {g}{6}+\frac {h}{6}+\frac {i}{6}\right )+\ln \left (x+1\right )\,\left (\frac {d}{6}-\frac {e}{6}+\frac {f}{6}-\frac {g}{6}+\frac {h}{6}-\frac {i}{6}\right )+\ln \left (x-2\right )\,\left (\frac {d}{12}+\frac {e}{6}+\frac {f}{3}+\frac {2\,g}{3}+\frac {4\,h}{3}+\frac {8\,i}{3}\right )-\ln \left (x+2\right )\,\left (\frac {d}{12}-\frac {e}{6}+\frac {f}{3}-\frac {2\,g}{3}+\frac {4\,h}{3}-\frac {8\,i}{3}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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